12=2x^2+4y^2

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Solution for 12=2x^2+4y^2 equation:


Simplifying
12 = 2x2 + 4y2

Solving
12 = 2x2 + 4y2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
12 + -2x2 = 2x2 + -2x2 + 4y2

Combine like terms: 2x2 + -2x2 = 0
12 + -2x2 = 0 + 4y2
12 + -2x2 = 4y2

Add '-12' to each side of the equation.
12 + -12 + -2x2 = -12 + 4y2

Combine like terms: 12 + -12 = 0
0 + -2x2 = -12 + 4y2
-2x2 = -12 + 4y2

Divide each side by '-2'.
x2 = 6 + -2y2

Simplifying
x2 = 6 + -2y2

Reorder the terms:
-6 + x2 + 2y2 = 6 + -2y2 + -6 + 2y2

Reorder the terms:
-6 + x2 + 2y2 = 6 + -6 + -2y2 + 2y2

Combine like terms: 6 + -6 = 0
-6 + x2 + 2y2 = 0 + -2y2 + 2y2
-6 + x2 + 2y2 = -2y2 + 2y2

Combine like terms: -2y2 + 2y2 = 0
-6 + x2 + 2y2 = 0

The solution to this equation could not be determined.

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